Correlation lets us know the association or absence of relationship between two variables ‘x’ and ‘y’. Regression, on the other end,predicts the value of the dependent variable based on the known value of the independent variable, assuming the existence of relationship between two or more variables.
Usage:
Correlation - to represent linear relationship between two variables.
Regression - to fit a best line and estimate one variable on the basis of another variable.
The term correlation is a combination of two words ‘Co’ (together) and relation (connection) between two quantities. Correlation is when, at the time of study of two variables, it is observed that a unit change in one variable is retaliated by an equivalent change in another variable. Or else, the variables are said to be uncorrelated when the movement in one variable does not amount to any movement in another variable in a specific direction.
It is a statistical technique that represents the strength of the connection between pairs of variables.
Correlation can be positive or negative. When the two variables move in the same direction, i.e. an increase in one variable will result in the corresponding increase in another variable and vice versa, then the variables are considered to be positively correlated.
On the contrary, when the two variables move in different directions, in such a way that an increase in one variable will result in a decrease in another variable and vice versa, This situation is known as a negative correlation. The measures of correlation may, for instance, be given as:
Karl Pearson’s Product-moment correlation coefficient
Spearman’s rank correlation coefficient
#cor() computes the correlation coefficient
#cor.test() test for association/correlation between paired samples;
#It returns both the correlation coefficient and the significance level(or p-value) of the correlation .
#The simplified formats are:
cor(x, y, method = c('pearson', 'kendall', 'spearman'))
cor.test(x, y, method=c('pearson', 'kendall', 'spearman'))
#install.packages('ggpubr')
library('ggpubr')
my_data <- mtcars
head(my_data, 6)
res <- cor.test(my_data$wt, my_data$mpg,
method = 'pearson')
res
The p-value of the test is less than the significance level alpha = 0.05. We can conclude that wt and mpg are significantly correlated with a correlation coefficient of -0.88 and p-value of 1,488e-11.
res <- cor.test(my_data$wt, my_data$mpg,
method = 'spearman')
res
library('ggpubr')
ggscatter(my_data, x = 'mpg', y = 'wt',
add = 'reg.line', conf.int = TRUE,
cor.coef = TRUE, cor.method = 'pearson',
xlab = 'Miles/(US) gallon', ylab = 'Weight (1000 lbs)')
Linear regression is used to predict the value of an outcome variable Y based on one or more input predictor variables X. The aim is to establish a linear relationship (a mathematical formula) between the predictor variable(s) and the response variable, so that, we can use this formula to estimate the value of the response Y, when only the predictors (Xs) values are known.
The mathematical equation can be generalized as follows:
Y = β1 + β2X + ϵ
where, β1 is the intercept and β2 is the slope. Collectively, they are called regression coefficients. ϵ is the error term, the part of Y the regression model is unable to explain
For this analysis, we will use the cars dataset that comes with R by default. cars is a standard built-in dataset, that makes it convenient to demonstrate linear regression in a simple and easy to understand fashion. You can access this dataset simply by typing in cars in your R console. You will find that it consists of 50 observations(rows) and 2 variables (columns) – dist and speed. Lets print out the first six observations here..
head(cars)
length(cars$speed)
Before we begin building the regression model, it is a good practice to analyze and understand the variables. The graphical analysis and correlation study below will help with this.
The aim of this exercise is to build a simple regression model that we can use to predict Distance (dist) by establishing a statistically significant linear relationship with Speed (speed). But before jumping in to the syntax, lets try to understand these variables graphically. Typically, for each of the independent variables (predictors), the following plots are drawn to visualize the following behavior:
Scatter plot: Visualize the linear relationship between the predictor and response
Box plot: To spot any outlier observations in the variable. Having outliers in your predictor can drastically affect the predictions as they can easily affect the direction/slope of the line of best fit.
Density plot: To see the distribution of the predictor variable. Ideally, a close to normal distribution (a bell shaped curve), without being skewed to the left or right is preferred. Let us see how to make each one of them.
Scatter plots can help visualize any linear relationships between the dependent (response) variable and independent (predictor) variables. Ideally, if you are having multiple predictor variables, a scatter plot is drawn for each one of them against the response, along with the line of best as seen below.
scatter.smooth(x=cars$speed, y=cars$dist, main='Dist ~ Speed') # scatterplot
The scatter plot along with the smoothing line above suggests a linearly increasing relationship between the ‘dist’ and ‘speed’ variables. This is a good thing, because one of the underlying assumptions in linear regression is that the relationship between the response and predictor variables is linear.
Generally, any datapoint that lies outside the 1.5 interquartile-range (1.5  IQR) is considered an outlier, where IQR is calculated as the distance between the 25th percentile and 75th percentile values for that variable.

par(mfrow=c(1, 2)) # divide graph area into 2 columns
boxplot(cars$speed, main='Speed', sub=paste('Outlier rows: ', boxplot.stats(cars$speed)$out)) # box plot for 'speed'
boxplot(cars$dist, main='Distance', sub=paste('Outlier rows: ', boxplot.stats(cars$dist)$out)) # box plot for 'distance'
Check if the response variable is close to normality
#install.packages('e1071')
# e1071: Functions for latent class analysis, short time Fourier transform, fuzzy clustering, support vector machines, shor# test path computation, bagged clustering, naive Bayes classifier, generalized k-nearest neighbour ...
library(e1071)
par(mfrow=c(1, 2)) # divide graph area in 2 columns
plot(density(cars$speed), main='Density Plot: Speed', ylab='Frequency', sub=paste('Skewness:', round(e1071::skewness(cars$speed), 2))) # density plot for 'speed'
polygon(density(cars$speed), col='red')
plot(density(cars$dist), main='Density Plot: Distance', ylab='Frequency', sub=paste('Skewness:', round(e1071::skewness(cars$dist), 2))) # density plot for 'dist'
polygon(density(cars$dist), col='red')
Correlation is a statistical measure that suggests the level of linear dependence between two variables, that occur in pair – just like what we have here in speed and dist. Correlation can take values between -1 to +1. If we observe for every instance where speed increases, the distance also increases along with it, then there is a high positive correlation between them and therefore the correlation between them will be closer to 1. The opposite is true for an inverse relationship, in which case, the correlation between the variables will be close to -1.
A value closer to 0 suggests a weak relationship between the variables. A low correlation (-0.2 < x < 0.2) probably suggests that much of variation of the response variable (Y) is unexplained by the predictor (X), in which case, we should probably look for better explanatory variables.
cor(cars$speed, cars$dist)
Now that we have seen the linear relationship pictorially in the scatter plot and by computing the correlation, lets see the syntax for building the linear model. The function used for building linear models is lm(). The lm() function takes in two main arguments, namely: 1. Formula 2. Data. The data is typically a data.frame and the formula is a object of class formula. But the most common convention is to write out the formula directly in place of the argument as written below.
linearMod <- lm(dist ~ speed, data=cars) # build linear regression model on full data
print(linearMod)
Now that we have built the linear model, we also have established the relationship between the predictor and response in the form of a mathematical formula for Distance (dist) as a function for speed. For the above output, you can notice the ‘Coefficients’ part having two components: Intercept: -17.579, speed: 3.932 These are also called the beta coefficients. In other words,
dist = Intercept + (β ∗ speed)
=> dist = −17.579 + 3.932∗speed
Now the linear model is built and we have a formula that we can use to predict the dist value if a corresponding speed is known. Is this enough to actually use this model? NO! Before using a regression model, you have to make sure it is statistically significant. Lets begin by printing the summary statistics for linearMod.
summary(linearMod) # model summary
The summary statistics above tells us a number of things. One of them is the model p-Value (bottom last line) and the p-Value of individual predictor variables (extreme right column under ‘Coefficients’). The p-Values are very important, because we can consider a linear model to be statistically significant only when both of these p-Values are less than the pre-determined statistical significance level, which is typically 0.05.
Null and alternate hypothesis
When there is a p-value, there is a null and alternative hypothesis associated with it. In Linear Regression, the Null Hypothesis is that the coefficients associated with the variables is equal to zero. The alternate hypothesis is that the coefficients are not equal to zero (i.e. there exists a relationship between the independent variable in question and the dependent variable).
t-value
We can interpret the t-value something like this. A larger t-value indicates that it is less likely that the coefficient is not equal to zero purely by chance. So the higher t-value, the better.
Pr(>|t|) or p-value is the probability that you get a t-value as high or higher than the observed value when the Null Hypothesis (the β coefficient is equal to zero or that there is no relationship) is true. So if the Pr(>|t|) is low, the coefficients are significant (significantly different from zero). If the Pr(>|t|) is high, the coefficients are not significant.
What this means to us? when p Value is less than significance level (< 0.05), we can safely reject the null hypothesthat the co-efficient β of the predictor is zero. In our case, both these p-Values are well below the 0.05 threshold, so we can conclude our model is indeed statistically significant.
It is absolutely important for the model to be statistically significant before we can go ahead and use it to predict (or estimate) the dependent variable.
When the model co-efficients and standard error are known, the formula for calculating t Statistic and p-Value is as follows:
t−Statistic = β−coefficient / Std.Error
modelSummary <- summary(linearMod) # capture model summary as an object
modelCoeffs <- modelSummary$coefficients # model coefficients
beta.estimate <- modelCoeffs['speed', 'Estimate'] # get beta estimate for speed
std.error <- modelCoeffs['speed', 'Std. Error'] # get std.error for speed
t_value <- beta.estimate/std.error # calc t statistic
p_value <- 2*pt(-abs(t_value), df=nrow(cars)-ncol(cars)) # calc p Value
f_statistic <- linearMod$fstatistic[1] # fstatistic
f <- summary(linearMod)$fstatistic # parameters for model p-value calc
# t-value
t_value
# p-value
p_value
#F-statistics
f[1]
summary(linearMod)
The actual information in a data is the total variation it contains. What R-Squared tells us is the proportion of variation in the dependent (response) variable that has been explained by this model.
R2 = (1−SSE) /SST
where, SSE is the sum of squared errors divided bythe sum of squared total.
R-squared = Explained variation / Total variation
R-squared is always between 0 and 100%:
0% indicates that the model explains none of the variability of the response data around its mean.
100% indicates that the model explains all the variability of the response data around its mean.
We don’t necessarily discard a model based on a low R-Squared value. Its a better practice to look at the AIC and prediction accuracy on validation sample when deciding on the efficacy of a model.
rsq <- function (x, y) cor(x, y) ^ 2
R2 <- rsq(cars$speed, cars$dist)
R2
Both standard errors and F-statistic are measures of goodness of fit.
std.error
f[1]
The Akaike’s information criterion - AIC (Akaike, 1974) and the Bayesian information criterion - BIC (Schwarz, 1978) are measures of the goodness of fit of an estimated statistical model and can also be used for model selection. Both criteria depend on the maximized value of the likelihood function L for the estimated model.
The AIC is defined as:
AIC = (−2) × ln(L) + (2×k)
where, k is the number of model parameters and the BIC is defined as:
BIC = (−2) × ln(L) + k × ln(n)
where n is the sample size.
For model comparison, the model with the lowest AIC and BIC score is preferred.
AIC(linearMod)
BIC(linearMod)
STATISTIC CRITERION
R-Squared Higher the better (> 0.70)
Adj R-Squared Higher the better
F-Statistic Higher the better
Std. Error Closer to zero the better
t-statistic Should be greater 1.96 for p-value to be less than 0.05
AIC Lower the better
BIC Lower the better
Mallows cp Should be close to the number of predictors in model
MAPE Lower the better
MSE Lower the better
Min_Max Accuracy Higher the better
MSE - (Mean squared error)
MAPE - (Mean absolute percentage error)
Min_Max Accuracy => mean(min(actual, predicted)/max(actual, predicted))
So far we have seen how to build a linear regression model using the whole dataset. If we build it that way, there is no way to tell how the model will perform with new data. So the preferred practice is to split your dataset into a 80:20 sample (training:test), then build the model on the 80% sample and then use the model to predict the dependent variable on test data.
Doing it this way, we will have the model predicted values for the 20% data (test) as well as the actuals (from the original dataset). By calculating accuracy measures (like min_max accuracy) and error rates (MAPE or MSE), we can find out the prediction accuracy of the model. Now, lets see how to actually do this.
Our model: dist = −17.579 + 3.932∗speed
Create the training (development) and test (validation) data samples from the original data.
# Create Training and Test data -
set.seed(100) # setting seed to reproduce results of random sampling
trainingRowIndex <- sample(1:nrow(cars), 0.8*nrow(cars)) # row indices for training data
trainingData <- cars[trainingRowIndex, ] # model training data
testData <- cars[-trainingRowIndex, ] # test data
Develop the model on the training data and use it to predict the distance on test data
# Build the model on training data -
lmMod <- lm(dist ~ speed, data=trainingData) # build the model
distPred <- predict(lmMod, testData) # predict distance
Review diagnostic measures.
summary (lmMod)
From the model summary, the model p value and predictor’s p value are less than the significance level, so we know we have a statistically significant model.
Calculate prediction accuracy and error rates
A simple correlation between the actuals and predicted values can be used as a form of accuracy measure. A higher correlation accuracy implies that the actuals and predicted values have similar directional movement, i.e. when the actuals values increase the predicteds also increase and vice-versa.
actuals_preds <- data.frame(cbind(actuals=testData$dist, predicteds=distPred)) # make actuals_predicteds dataframe.
correlation_accuracy <- cor(actuals_preds)
correlation_accuracy
head(actuals_preds)
Now lets calculate the Min Max accuracy and MAPE:
min_max_accuracy <- mean(apply(actuals_preds, 1, min) / apply(actuals_preds, 1, max))
min_max_accuracy
mape <- mean(abs((actuals_preds$predicteds - actuals_preds$actuals))/actuals_preds$actuals)
mape
Suppose, the model predicts satisfactorily on the 20% split (test data), is that enough to believe that your model will perform equally well all the time? It is important to rigorously test the model’s performance as much as possible. One way is to ensure that the model equation you have will perform well, when it is ‘built’ on a different subset of training data and predicted on the remaining data.
How to do this is? Split your data into ‘k’ mutually exclusive random sample portions. Keeping each portion as test data, we build the model on the remaining (k-1 portion) data and calculate the mean squared error of the predictions. This is done for each of the ‘k’ random sample portions. Then finally, the average of these mean squared errors (for ‘k’ portions) is computed. We can use this metric to compare different linear models.
By doing this, we need to check two things:
If the model’s prediction accuracy isn’t varying too much for any one particular sample, and
If the lines of best fit don’t vary too much with respect the the slope and level.
In other words, they should be parallel and as close to each other as possible. You can find a more detailed explanation for interpreting the cross validation charts when you learn about advanced linear model building.

#install.packages('DAAG')
library(DAAG)
library(ggplot2)
cvResults <- suppressWarnings(CVlm(cars, form.lm = dist ~ speed, m=5, dots=FALSE, seed=29, legend.pos='topleft', printit=FALSE, main='Small symbols are predicted values while bigger ones are actuals.')); # performs the CV
attr(cvResults, 'ms') # => 251.2783 mean squared error
Building a linear regression model is only half of the work. In order to actually be usable in practice, the model should conform to the assumptions of linear regression.
#install.packages('gvlma')
library('gvlma')
par(mfrow=c(2,2)) # draw 4 plots in same window
mod <- lm(dist ~ speed, data=cars)
gvlma::gvlma(mod)
plot(mod)
From the above plot the data points: 23, 35 and 49 are marked as outliers. Lets remove them from the data and re-build the model.
par(mfrow=c(2,2))
mod <- lm(dist ~ speed, data=cars[-c(23, 35, 49), ])
gvlma::gvlma(mod)
#install.packages('DAAG')
library(DAAG)
library(ggplot2)
new_data <- (cars[-c(23, 35, 49), ])
cvResults <- suppressWarnings(CVlm(new_data, form.lm = dist ~ speed, m=5, dots=FALSE, seed=29, legend.pos='topleft', printit=FALSE, main='Small symbols are predicted values while bigger ones are actuals.')); # performs the CV
attr(cvResults, 'ms')
summary (mod)
R-squard and Adjusted R-squared improved MSE decreased twice
# Create Training and Test data -
set.seed(100) # setting seed to reproduce results of random sampling
new_data <- (cars[-c(23, 35, 49), ])
trainingRowIndex <- sample(1:nrow(new_data), 0.8*nrow(new_data)) # row indices for training data
trainingData <- cars[trainingRowIndex, ] # model training data
testData <- cars[-trainingRowIndex, ] # test data
# Build the model on training data -
lmMod <- lm(dist ~ speed, data=trainingData) # build the model
distPred <- predict(lmMod, testData) # predict distance
actuals_preds <- data.frame(cbind(actuals=testData$dist, predicteds=distPred)) # make actuals_predicteds dataframe.
correlation_accuracy <- cor(actuals_preds)
correlation_accuracy
min_max_accuracy <- mean(apply(actuals_preds, 1, min) / apply(actuals_preds, 1, max))
min_max_accuracy
mape <- mean(abs((actuals_preds$predicteds - actuals_preds$actuals))/actuals_preds$actuals)
mape
# Multiple Linear Regression Example
fit <- lm(y ~ x1 + x2 + x3, data=mydata)
summary(fit) # show results
#Optional: Other useful functions (may be usefull)
coefficients(fit) # model coefficients
confint(fit, level=0.95) # CIs for model parameters
fitted(fit) # predicted values
residuals(fit) # residuals
anova(fit) # anova table
vcov(fit) # covariance matrix for model parameters
influence(fit) # regression diagnostics
Diagnostic plots provide checks for heteroscedasticity, normality, and influential observerations.
# diagnostic plots
layout(matrix(c(1,2,3,4),2,2)) # optional 4 graphs/page
plot(fit)
You can compare nested models with the anova( ) function. The following code provides a simultaneous test that x3 and x4 add to linear prediction above and beyond x1 and x2.
# compare models
fit1 <- lm(y ~ x1 + x2 + x3 + x4, data=mydata)
fit2 <- lm(y ~ x1 + x2)
anova(fit1, fit2)
You can do K-Fold cross-validation using the cv.lm( ) function in the DAAG package.
# K-fold cross-validation
library(DAAG)
cv.lm(df=mydata, fit, m=3) # 3 fold cross-validation
Examples of data
We’ll use the marketing data set [datarium package], which contains the impact of the amount of money spent on three advertising medias (youtube, facebook and newspaper) on sales.
We want to build a model for estimating sales based on the advertising budget invested in youtube, facebook and newspaper, as follow:
sales = b0 + b1 youtube + b2 facebook + b3 * newspaper
library(DAAG)
#getwd()
marketing <- read.table('~/Desktop/Statistics_R/data/marketing.tsv', sep='\t', header=TRUE)
head(marketing, 4)
fit <- lm(sales ~ youtube + facebook + newspaper, data=marketing)
summary(fit)
fit <- lm(sales ~ youtube + facebook, data=marketing)
summary(fit)
For example, for a fixed amount of youtube and newspaper advertising budget, spending an additional 1 000 dollars on facebook advertising leads to an increase in sales by approximately 0.1885*1000 = 189 sale units, on average.
Reference:
https://www.youtube.com/watch?v=bPFNxD3Yg6U
http://www.r-tutor.com/elementary-statistics
https://www.tutorialspoint.com/r/index.htm
https://keydifferences.com/difference-between-correlation-and-regression.html
https://www.statmethods.net/stats/correlations.html
http://www.sthda.com/english/wiki/correlation-test-between-two-variables-in-r